Home Latest News Tottenham receive boost as superstar returns to training ahead of City clash

Tottenham receive boost as superstar returns to training ahead of City clash

LONDON, ENGLAND - APRIL 01: Dele Alli of Tottenham Hotspur celebrates after scoring his side's third goal during the Premier League match between Chelsea and Tottenham Hotspur at Stamford Bridge on April 1, 2018 in London, England. (Photo by Michael Regan/Getty Images)

Tottenham Hotspur could be handed a major boost ahead of their Champions League clash against Manchester City tomorrow. Midfielder Dele Alli, who broke his hand in the first leg, trained with the side this week. He has, as a result, been named in Spurs’ side that will travel to the Etihad.

Despite featuring in light training, the English midfielder will have to be assessed prior to kick off. However, with Spurs holding a slender 1-0 lead, they could opt to take a risk and start Alli.

4 out, 2 in

One person who will certainly not feature for Spurs is star striker Harry Kane, who has been ruled out for the rest of the season after picking up a knock in the reverse fixture.

Kane has been stellar for Spurs every time he has played this season and his absence will be a major blow.

Midfielder Erik Lamela who has missed Spurs’ last few games due to a hamstring injury is also set to return and will need to pass a late fitness test to prove his readiness.

Defensive duo of Serge Aurier and Eric Dier, as well as midfield general Harry Winks, remain on the sidelines.

Aguero passed fit

For City, on the other hand, Sergio Aguero has been passed fit. Aguero was substituted in City’s victory over Crystal Palace over the weekend, amid concerns over his ankle, but he seems to have recovered in time.

Brazilian midfielder Fernandinho has also trained with the side and could make the bench.

City dominated much of the possession in the first leg, but failed to breach an organized Spurs defence. They will have to score at the Etihad if they are to harbor hopes of qualifying for the semifinals.